Particles of charge Q1 = +64 µC, Q2 = +53 µC, and Q3 = -80 µC are placed in a line (Fig. 16-37). The center on

Particles of charge Q1 = +64 µC, Q2 = +53 µC, and Q3 = -80 µC are placed in a line (Fig. 16-37). The center one is 0.35 m from each of the others. Calculate the net force on each charge due to the other two.





Image: http://i27.tinypic.com/nvbno8.gif








Force on Q1


Magnitude=___N





Force on Q2


Magnitude=___N





Force on Q3


Magnitude=___N











Please explain your answer. Also, I have several other physics questions open, so if you get a chance, please look those up as well. Thanks!!

Particles of charge Q1 = +64 µC, Q2 = +53 µC, and Q3 = -80 µC are placed in a line (Fig. 16-37). The center on
The magnitude of force from one to the other is


F=C*q1*q2/d^2








Q1


F=-C*q1*(q2/0.35^2+q3/0.70^2)


be careful of signs


F= -155 N








Q2


F= C*q2*(q1/0.35^2-q3/0.35^2)


note the signs


F=560 N











Q3


F= -C*q3*(q1/0.7^2+q2/0.35^2)


note the signs


F=405 N





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