Determine the terminal voltage of each battery in Fig. 19-44 (R = 8.8 ohms ).
18 V battery _________ V
12 V battery _________ V
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Determine the terminal voltage of each battery in Fig. 19-44 (R = 8.8 ohms). Figure Link....?
Sum the voltages around the loop to get 18 - 12 - I*∑R = 0. 6 - I*(1+2+8.8) = 0; 6 - I*11.8 = 0
I = 6/11.8 = 0.508 A.
Although it is not clear, it appears that the 1 and 2 ohm resistors are the internal resistances of the batteries. If so, the battery voltage of the larger (18V) battery is then 18 - 1*I = 18 - 0.508 = 17.492V. In the case of the 12V battery, current is flowing in reverse through that battery so its terminal voltage will be 12 + 2*0.508 = 13.106V
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