If 25.6 V is applied across the whole network of Fig. 19-52, calculate the voltage across each capacitor. 3.00

If 25.6 V is applied across the whole network of Fig. 19-52, calculate the voltage across each capacitor.


3.00 µF capacitor __________ V


4.00 µF capacitor __________V


2.00 µF capacitor __________ V





Fig. 19-52 Link ..


http://img.photobucket.com/albums/v706/E...

If 25.6 V is applied across the whole network of Fig. 19-52, calculate the voltage across each capacitor. 3.00
Capacitor_________Impedance (Ω)


3 µF______________1062


4 µF______________796.2


2 µF______________1592.4





i 1 is current thro` 3µF and 4µF capacitors


i 2 is current thro` 2 µF capacitor.





i 1 = (25.6 / 1858.2) x 1000 mA = 13.8 mA


i 2 = (25.6 / 1592.4) x 1000 mA = 16.1 mA
Reply:Thank you for vote Report It

Reply:1/3+1/4+1/2=1/c


c=12/13


c=q/v


find q


for each capacitor v=q/c
Reply:2.00µF = 25.6 V


Because it is connected in parallel





4.00µF and 3.00µF are in series


Charge between is the same which Q .





4.00µF = Q/V1


3.00µF = Q/V2





Combined = (4x3)/(4+3) = 12/7 µF





12/7µF = Q/25.6


Q = 1536/35 µC





4.00µF = (1536/35µC) / V1


V1 = 10.97 V


3.00µF = (1536/35µC)/V2


V2 = 14.63 V